-3a+4(2a+2)=3(4a-3)-4

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Solution for -3a+4(2a+2)=3(4a-3)-4 equation: 



-3a+4(2a+2)=3(4a-3)-4

We move all terms to the left:

-3a+4(2a+2)-(3(4a-3)-4)=0

We multiply parentheses

-3a+8a-(3(4a-3)-4)+8=0



We calculate terms in parentheses: -(3(4a-3)-4), so:

3(4a-3)-4

We multiply parentheses

12a-9-4

We add all the numbers together, and all the variables

12a-13

Back to the equation:

-(12a-13)



We add all the numbers together, and all the variables

5a-(12a-13)+8=0

We get rid of parentheses

5a-12a+13+8=0

We add all the numbers together, and all the variables

-7a+21=0

We move all terms containing a to the left, all other terms to the right

-7a=-21

a=-21/-7

a=+3

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