M+(m-1)/2=1+(m-2)/3

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Solution for M+(m-1)/2=1+(m-2)/3 equation: 



+(M-1)/2=1+(M-2)/3

We move all terms to the left:

+(M-1)/2-(1+(M-2)/3)=0

We calculate fractions


M/()+(-(1+(M-2)*2)/()=0



We calculate terms in parentheses: +(-(1+(M-2)*2)/(), so:

-(1+(M-2)*2)/(

We multiply all the terms by the denominator


-(1+(M-2)*2)



We calculate terms in parentheses: -(1+(M-2)*2), so:

1+(M-2)*2

determiningTheFunctionDomain
(M-2)*2+1

We multiply parentheses

2M-4+1

We add all the numbers together, and all the variables

2M-3

Back to the equation:

-(2M-3)



We get rid of parentheses

-2M+3

Back to the equation:

+(-2M+3)



We get rid of parentheses

M/()-2M+3=0

We multiply all the terms by the denominator


M-2M*()+3*()=0

We add all the numbers together, and all the variables

M-2M*()=0

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