K-(k-1)/2=1-(k-3)/3

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Solution for K-(k-1)/2=1-(k-3)/3 equation: 



-(K-1)/2=1-(K-3)/3

We move all terms to the left:

-(K-1)/2-(1-(K-3)/3)=0

We calculate fractions


(-K)/()+(-(1-(K-3)*2)/()=0



We calculate terms in parentheses: +(-(1-(K-3)*2)/(), so:

-(1-(K-3)*2)/(

We multiply all the terms by the denominator


-(1-(K-3)*2)



We calculate terms in parentheses: -(1-(K-3)*2), so:

1-(K-3)*2

determiningTheFunctionDomain
-(K-3)*2+1

We multiply parentheses

-2K+6+1

We add all the numbers together, and all the variables

-2K+7

Back to the equation:

-(-2K+7)



We get rid of parentheses

2K-7

Back to the equation:

+(2K-7)



We add all the numbers together, and all the variables

(-1K)/()+(2K-7)=0

We get rid of parentheses

(-1K)/()+2K-7=0

We multiply all the terms by the denominator


(-1K)+2K*()-7*()=0

We add all the numbers together, and all the variables

(-1K)+2K*()=0

We get rid of parentheses

-1K+2K*()=0

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