16-(7x+3)=41

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Solution for 16-(7x+3)=41 equation: 



16-(7x+3)=41

We move all terms to the left:

16-(7x+3)-(41)=0

We add all the numbers together, and all the variables

-(7x+3)-25=0

We get rid of parentheses

-7x-3-25=0

We add all the numbers together, and all the variables

-7x-28=0

We move all terms containing x to the left, all other terms to the right

-7x=28

x=28/-7

x=-4

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