9x-3(x-2)=4(x-4)

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Solution for 9x-3(x-2)=4(x-4) equation: 



9x-3(x-2)=4(x-4)

We move all terms to the left:

9x-3(x-2)-(4(x-4))=0

We multiply parentheses

9x-3x-(4(x-4))+6=0



We calculate terms in parentheses: -(4(x-4)), so:

4(x-4)

We multiply parentheses

4x-16

Back to the equation:

-(4x-16)



We add all the numbers together, and all the variables

6x-(4x-16)+6=0

We get rid of parentheses

6x-4x+16+6=0

We add all the numbers together, and all the variables

2x+22=0

We move all terms containing x to the left, all other terms to the right

2x=-22

x=-22/2

x=-11

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