4m-2(3+2m)+m(2m+4)=0

Solution for 4m-2(3+2m)+m(2m+4)=0 equation:

4m-2(3+2m)+m(2m+4)=0

We add all the numbers together, and all the variables

4m-2(2m+3)+m(2m+4)=0

We multiply parentheses

2m^2+4m-4m+4m-6=0

We add all the numbers together, and all the variables

2m^2+4m-6=0

a = 2; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·2·(-6)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8}{2*2}=\frac{-12}{4}
=-3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8}{2*2}=\frac{4}{4}
=1
$