X+(x+25)3x=435

Solution for X+(x+25)3x=435 equation:

X+(X+25)3X=435

We move all terms to the left:

X+(X+25)3X-(435)=0

We multiply parentheses

3X^2+X+75X-435=0

We add all the numbers together, and all the variables

3X^2+76X-435=0

a = 3; b = 76; c = -435;
Δ = b2-4ac
Δ = 762-4·3·(-435)
Δ = 10996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10996}=\sqrt{4*2749}=\sqrt{4}*\sqrt{2749}=2\sqrt{2749}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-2\sqrt{2749}}{2*3}=\frac{-76-2\sqrt{2749}}{6}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+2\sqrt{2749}}{2*3}=\frac{-76+2\sqrt{2749}}{6}
$