F(4p+3)=8-5(4p+3)

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Solution for F(4p+3)=8-5(4p+3) equation: 



(4F+3)=8-5(4F+3)

We move all terms to the left:

(4F+3)-(8-5(4F+3))=0

We get rid of parentheses

4F-(8-5(4F+3))+3=0



We calculate terms in parentheses: -(8-5(4F+3)), so:

8-5(4F+3)

determiningTheFunctionDomain
-5(4F+3)+8

We multiply parentheses

-20F-15+8

We add all the numbers together, and all the variables

-20F-7

Back to the equation:

-(-20F-7)



We get rid of parentheses

4F+20F+7+3=0

We add all the numbers together, and all the variables

24F+10=0

We move all terms containing F to the left, all other terms to the right

24F=-10

F=-10/24

F=-5/12

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