-3(2v-4)+5v=3(v+2)

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Solution for -3(2v-4)+5v=3(v+2) equation: 



-3(2v-4)+5v=3(v+2)

We move all terms to the left:

-3(2v-4)+5v-(3(v+2))=0

We add all the numbers together, and all the variables

5v-3(2v-4)-(3(v+2))=0

We multiply parentheses

5v-6v-(3(v+2))+12=0



We calculate terms in parentheses: -(3(v+2)), so:

3(v+2)

We multiply parentheses

3v+6

Back to the equation:

-(3v+6)



We add all the numbers together, and all the variables

-1v-(3v+6)+12=0

We get rid of parentheses

-1v-3v-6+12=0

We add all the numbers together, and all the variables

-4v+6=0

We move all terms containing v to the left, all other terms to the right

-4v=-6

v=-6/-4

v=1+1/2

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