-2(-8y+9)-6y=2(y-4)-4

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Solution for -2(-8y+9)-6y=2(y-4)-4 equation: 



-2(-8y+9)-6y=2(y-4)-4

We move all terms to the left:

-2(-8y+9)-6y-(2(y-4)-4)=0

We add all the numbers together, and all the variables

-6y-2(-8y+9)-(2(y-4)-4)=0

We multiply parentheses

-6y+16y-(2(y-4)-4)-18=0



We calculate terms in parentheses: -(2(y-4)-4), so:

2(y-4)-4

We multiply parentheses

2y-8-4

We add all the numbers together, and all the variables

2y-12

Back to the equation:

-(2y-12)



We add all the numbers together, and all the variables

10y-(2y-12)-18=0

We get rid of parentheses

10y-2y+12-18=0

We add all the numbers together, and all the variables

8y-6=0

We move all terms containing y to the left, all other terms to the right

8y=6

y=6/8

y=3/4

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