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(A)=(5A-1)(3A-2)
We move all terms to the left:
(A)-((5A-1)(3A-2))=0
We multiply parentheses ..
-((+15A^2-10A-3A+2))+A=0
We calculate terms in parentheses: -((+15A^2-10A-3A+2)), so:We add all the numbers together, and all the variables
(+15A^2-10A-3A+2)
We get rid of parentheses
15A^2-10A-3A+2
We add all the numbers together, and all the variables
15A^2-13A+2
Back to the equation:
-(15A^2-13A+2)
A-(15A^2-13A+2)=0
We get rid of parentheses
-15A^2+A+13A-2=0
We add all the numbers together, and all the variables
-15A^2+14A-2=0
a = -15; b = 14; c = -2;
Δ = b2-4ac
Δ = 142-4·(-15)·(-2)
Δ = 76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{76}=\sqrt{4*19}=\sqrt{4}*\sqrt{19}=2\sqrt{19}$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{19}}{2*-15}=\frac{-14-2\sqrt{19}}{-30} $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{19}}{2*-15}=\frac{-14+2\sqrt{19}}{-30} $
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