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7-4(3x-1)+5=3x-(2x+1)
We move all terms to the left:
7-4(3x-1)+5-(3x-(2x+1))=0
We add all the numbers together, and all the variables
-4(3x-1)-(3x-(2x+1))+12=0
We multiply parentheses
-12x-(3x-(2x+1))+4+12=0
We calculate terms in parentheses: -(3x-(2x+1)), so:We add all the numbers together, and all the variables
3x-(2x+1)
We get rid of parentheses
3x-2x-1
We add all the numbers together, and all the variables
x-1
Back to the equation:
-(x-1)
-12x-(x-1)+16=0
We get rid of parentheses
-12x-x+1+16=0
We add all the numbers together, and all the variables
-13x+17=0
We move all terms containing x to the left, all other terms to the right
-13x=-17
x=-17/-13
x=1+4/13
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