(3*x*x-4)/(3x+1)=x+1

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Solution for (3*x*x-4)/(3x+1)=x+1 equation: 



(3x*x-4)/(3x+1)=x+1

We move all terms to the left:

(3x*x-4)/(3x+1)-(x+1)=0



Domain of the equation: (3x+1)!=0

We move all terms containing x to the left, all other terms to the right

3x!=-1

x!=-1/3

x!=-1/3

x∈R



We get rid of parentheses

(3x*x-4)/(3x+1)-x-1=0

We multiply all the terms by the denominator


(3x*x-4)-x*(3x+1)-1*(3x+1)=0

We multiply parentheses

-3x^2+(3x*x-4)-x-1*(3x+1)=0

We get rid of parentheses

-3x^2+3x*x-x-1*(3x+1)-4=0

We add all the numbers together, and all the variables

-3x^2-1x+3x*x-1*(3x+1)-4=0

Wy multiply elements

-3x^2+3x^2-1x-1*(3x+1)-4=0

We add all the numbers together, and all the variables

-1x-1*(3x+1)-4=0

We move all terms containing x to the left, all other terms to the right

-1x-1*(3x+1)=4

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