(x+5)2=(x-3)2+8x

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Solution for (x+5)2=(x-3)2+8x equation: 



(x+5)2=(x-3)2+8x

We move all terms to the left:

(x+5)2-((x-3)2+8x)=0

We multiply parentheses

2x-((x-3)2+8x)+10=0



We calculate terms in parentheses: -((x-3)2+8x), so:

(x-3)2+8x

We add all the numbers together, and all the variables

8x+(x-3)2

We multiply parentheses

8x+2x-6

We add all the numbers together, and all the variables

10x-6

Back to the equation:

-(10x-6)



We get rid of parentheses

2x-10x+6+10=0

We add all the numbers together, and all the variables

-8x+16=0

We move all terms containing x to the left, all other terms to the right

-8x=-16

x=-16/-8

x=+2

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