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9x-3=3(3+x)
We move all terms to the left:
9x-3-(3(3+x))=0
We add all the numbers together, and all the variables
9x-(3(x+3))-3=0
We calculate terms in parentheses: -(3(x+3)), so:We get rid of parentheses
3(x+3)
We multiply parentheses
3x+9
Back to the equation:
-(3x+9)
9x-3x-9-3=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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