10=2x+2(2x-2)

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Solution for 10=2x+2(2x-2) equation: 



10=2x+2(2x-2)

We move all terms to the left:

10-(2x+2(2x-2))=0



We calculate terms in parentheses: -(2x+2(2x-2)), so:

2x+2(2x-2)

We multiply parentheses

2x+4x-4

We add all the numbers together, and all the variables

6x-4

Back to the equation:

-(6x-4)



We get rid of parentheses

-6x+4+10=0

We add all the numbers together, and all the variables

-6x+14=0

We move all terms containing x to the left, all other terms to the right

-6x=-14

x=-14/-6

x=2+1/3

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