4y-38=7(y-2)

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Solution for 4y-38=7(y-2) equation: 



4y-38=7(y-2)

We move all terms to the left:

4y-38-(7(y-2))=0



We calculate terms in parentheses: -(7(y-2)), so:

7(y-2)

We multiply parentheses

7y-14

Back to the equation:

-(7y-14)



We get rid of parentheses

4y-7y+14-38=0

We add all the numbers together, and all the variables

-3y-24=0

We move all terms containing y to the left, all other terms to the right

-3y=24

y=24/-3

y=-8

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