108+2y=2(5y+8)+2(2y+10)

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Solution for 108+2y=2(5y+8)+2(2y+10) equation: 



108+2y=2(5y+8)+2(2y+10)

We move all terms to the left:

108+2y-(2(5y+8)+2(2y+10))=0



We calculate terms in parentheses: -(2(5y+8)+2(2y+10)), so:

2(5y+8)+2(2y+10)

We multiply parentheses

10y+4y+16+20

We add all the numbers together, and all the variables

14y+36

Back to the equation:

-(14y+36)



We get rid of parentheses

2y-14y-36+108=0

We add all the numbers together, and all the variables

-12y+72=0

We move all terms containing y to the left, all other terms to the right

-12y=-72

y=-72/-12

y=+6

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