9x^2-50x-8=0

Solution for 9x^2-50x-8=0 equation:

9x^2-50x-8=0

a = 9; b = -50; c = -8;
Δ = b2-4ac
Δ = -502-4·9·(-8)
Δ = 2788
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2788}=\sqrt{4*697}=\sqrt{4}*\sqrt{697}=2\sqrt{697}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{697}}{2*9}=\frac{50-2\sqrt{697}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{697}}{2*9}=\frac{50+2\sqrt{697}}{18}
$