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4(2x-5)=4(x-3)
We move all terms to the left:
4(2x-5)-(4(x-3))=0
We multiply parentheses
8x-(4(x-3))-20=0
We calculate terms in parentheses: -(4(x-3)), so:We get rid of parentheses
4(x-3)
We multiply parentheses
4x-12
Back to the equation:
-(4x-12)
8x-4x+12-20=0
We add all the numbers together, and all the variables
4x-8=0
We move all terms containing x to the left, all other terms to the right
4x=8
x=8/4
x=2
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