17+2b=5(b-2)

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Solution for 17+2b=5(b-2) equation: 



17+2b=5(b-2)

We move all terms to the left:

17+2b-(5(b-2))=0



We calculate terms in parentheses: -(5(b-2)), so:

5(b-2)

We multiply parentheses

5b-10

Back to the equation:

-(5b-10)



We get rid of parentheses

2b-5b+10+17=0

We add all the numbers together, and all the variables

-3b+27=0

We move all terms containing b to the left, all other terms to the right

-3b=-27

b=-27/-3

b=+9

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