(9x-1)-(1-4x)=(2x+8)+(9x-10)

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Solution for (9x-1)-(1-4x)=(2x+8)+(9x-10) equation: 



(9x-1)-(1-4x)=(2x+8)+(9x-10)

We move all terms to the left:

(9x-1)-(1-4x)-((2x+8)+(9x-10))=0

We add all the numbers together, and all the variables

(9x-1)-(-4x+1)-((2x+8)+(9x-10))=0

We get rid of parentheses

9x+4x-((2x+8)+(9x-10))-1-1=0



We calculate terms in parentheses: -((2x+8)+(9x-10)), so:

(2x+8)+(9x-10)

We get rid of parentheses

2x+9x+8-10

We add all the numbers together, and all the variables

11x-2

Back to the equation:

-(11x-2)



We add all the numbers together, and all the variables

13x-(11x-2)-2=0

We get rid of parentheses

13x-11x+2-2=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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