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9-(x-3)=6(x+10)
We move all terms to the left:
9-(x-3)-(6(x+10))=0
We get rid of parentheses
-x-(6(x+10))+3+9=0
We calculate terms in parentheses: -(6(x+10)), so:We add all the numbers together, and all the variables
6(x+10)
We multiply parentheses
6x+60
Back to the equation:
-(6x+60)
-1x-(6x+60)+12=0
We get rid of parentheses
-1x-6x-60+12=0
We add all the numbers together, and all the variables
-7x-48=0
We move all terms containing x to the left, all other terms to the right
-7x=48
x=48/-7
x=-6+6/7
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