6(t+2)=4(t-2)

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Solution for 6(t+2)=4(t-2) equation: 



6(t+2)=4(t-2)

We move all terms to the left:

6(t+2)-(4(t-2))=0

We multiply parentheses

6t-(4(t-2))+12=0



We calculate terms in parentheses: -(4(t-2)), so:

4(t-2)

We multiply parentheses

4t-8

Back to the equation:

-(4t-8)



We get rid of parentheses

6t-4t+8+12=0

We add all the numbers together, and all the variables

2t+20=0

We move all terms containing t to the left, all other terms to the right

2t=-20

t=-20/2

t=-10

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