4x-4(3-2x)=3(x-5)-51

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Solution for 4x-4(3-2x)=3(x-5)-51 equation: 



4x-4(3-2x)=3(x-5)-51

We move all terms to the left:

4x-4(3-2x)-(3(x-5)-51)=0

We add all the numbers together, and all the variables

4x-4(-2x+3)-(3(x-5)-51)=0

We multiply parentheses

4x+8x-(3(x-5)-51)-12=0



We calculate terms in parentheses: -(3(x-5)-51), so:

3(x-5)-51

We multiply parentheses

3x-15-51

We add all the numbers together, and all the variables

3x-66

Back to the equation:

-(3x-66)



We add all the numbers together, and all the variables

12x-(3x-66)-12=0

We get rid of parentheses

12x-3x+66-12=0

We add all the numbers together, and all the variables

9x+54=0

We move all terms containing x to the left, all other terms to the right

9x=-54

x=-54/9

x=-6

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