9(y-4)-7y=5(4y-2)

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Solution for 9(y-4)-7y=5(4y-2) equation: 



9(y-4)-7y=5(4y-2)

We move all terms to the left:

9(y-4)-7y-(5(4y-2))=0

We add all the numbers together, and all the variables

-7y+9(y-4)-(5(4y-2))=0

We multiply parentheses

-7y+9y-(5(4y-2))-36=0



We calculate terms in parentheses: -(5(4y-2)), so:

5(4y-2)

We multiply parentheses

20y-10

Back to the equation:

-(20y-10)



We add all the numbers together, and all the variables

2y-(20y-10)-36=0

We get rid of parentheses

2y-20y+10-36=0

We add all the numbers together, and all the variables

-18y-26=0

We move all terms containing y to the left, all other terms to the right

-18y=26

y=26/-18

y=-1+4/9

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