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3(x+3)=7(x-1)-12
We move all terms to the left:
3(x+3)-(7(x-1)-12)=0
We multiply parentheses
3x-(7(x-1)-12)+9=0
We calculate terms in parentheses: -(7(x-1)-12), so:We get rid of parentheses
7(x-1)-12
We multiply parentheses
7x-7-12
We add all the numbers together, and all the variables
7x-19
Back to the equation:
-(7x-19)
3x-7x+19+9=0
We add all the numbers together, and all the variables
-4x+28=0
We move all terms containing x to the left, all other terms to the right
-4x=-28
x=-28/-4
x=+7
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