5(4z+1)-9=136

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Solution for 5(4z+1)-9=136 equation: 



5(4z+1)-9=136

We move all terms to the left:

5(4z+1)-9-(136)=0

We add all the numbers together, and all the variables

5(4z+1)-145=0

We multiply parentheses

20z+5-145=0

We add all the numbers together, and all the variables

20z-140=0

We move all terms containing z to the left, all other terms to the right

20z=140

z=140/20

z=7

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