2/3(6c-18)+3/4(8c+32=-18

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Solution for 2/3(6c-18)+3/4(8c+32=-18 equation: 



2/3(6c-18)+3/4(8c+32=-18

We move all terms to the left:

2/3(6c-18)+3/4(8c+32-(-18)=0



Domain of the equation: 3(6c-18)!=0

c∈R





Domain of the equation: 4(8c+32-(-18)!=0

c∈R



We calculate fractions


(8c8/(3(6c-18)*4(8c+32-(-18))+(9c6/(3(6c-18)*4(8c+32-(-18))=0



We calculate terms in parentheses: +(8c8/(3(6c-18)*4(8c+32-(-18))+(9c6/(3(6c-18)*4(8c+32-(-18)), so:

8c8/(3(6c-18)*4(8c+32-(-18))+(9c6/(3(6c-18)*4(8c+32-(-18)

We can not solve this equation

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