9(f-1)=5+4(f+1)-3

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Solution for 9(f-1)=5+4(f+1)-3 equation: 



9(f-1)=5+4(f+1)-3

We move all terms to the left:

9(f-1)-(5+4(f+1)-3)=0

We multiply parentheses

9f-(5+4(f+1)-3)-9=0



We calculate terms in parentheses: -(5+4(f+1)-3), so:

5+4(f+1)-3

determiningTheFunctionDomain
4(f+1)+5-3

We add all the numbers together, and all the variables

4(f+1)+2

We multiply parentheses

4f+4+2

We add all the numbers together, and all the variables

4f+6

Back to the equation:

-(4f+6)



We get rid of parentheses

9f-4f-6-9=0

We add all the numbers together, and all the variables

5f-15=0

We move all terms containing f to the left, all other terms to the right

5f=15

f=15/5

f=3

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