4(n-1)-3=2(n+1)+1

Solution for 4(n-1)-3=2(n+1)+1 equation:

4(n-1)-3=2(n+1)+1

We move all terms to the left:

4(n-1)-3-(2(n+1)+1)=0

We multiply parentheses

4n-(2(n+1)+1)-4-3=0


We calculate terms in parentheses: -(2(n+1)+1), so:

2(n+1)+1

We multiply parentheses

2n+2+1

We add all the numbers together, and all the variables

2n+3

Back to the equation:

-(2n+3)


We add all the numbers together, and all the variables

4n-(2n+3)-7=0

We get rid of parentheses

4n-2n-3-7=0

We add all the numbers together, and all the variables

2n-10=0

We move all terms containing n to the left, all other terms to the right

2n=10

n=10/2

n=5