(1)/(3)h-((8)/(3)h-12)=(2)/(3)h-6

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Solution for (1)/(3)h-((8)/(3)h-12)=(2)/(3)h-6 equation: 



(1)/(3)h-((8)/(3)h-12)=(2)/(3)h-6

We move all terms to the left:

(1)/(3)h-((8)/(3)h-12)-((2)/(3)h-6)=0



Domain of the equation: 3h!=0

h!=0/3

h!=0

h∈R





Domain of the equation: 3h-12)!=0

h∈R





Domain of the equation: 3h-6)!=0

h∈R



We get rid of parentheses

1/3h-8/3h-2/3h+12+6=0

We multiply all the terms by the denominator


12*3h+6*3h+1-8-2=0

We add all the numbers together, and all the variables

12*3h+6*3h-9=0

Wy multiply elements

36h+18h-9=0

We add all the numbers together, and all the variables

54h-9=0

We move all terms containing h to the left, all other terms to the right

54h=9

h=9/54

h=1/6

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