10(y-1)-14=3(y+1)+15

Solution for 10(y-1)-14=3(y+1)+15 equation:

10(y-1)-14=3(y+1)+15

We move all terms to the left:

10(y-1)-14-(3(y+1)+15)=0

We multiply parentheses

10y-(3(y+1)+15)-10-14=0


We calculate terms in parentheses: -(3(y+1)+15), so:

3(y+1)+15

We multiply parentheses

3y+3+15

We add all the numbers together, and all the variables

3y+18

Back to the equation:

-(3y+18)


We add all the numbers together, and all the variables

10y-(3y+18)-24=0

We get rid of parentheses

10y-3y-18-24=0

We add all the numbers together, and all the variables

7y-42=0

We move all terms containing y to the left, all other terms to the right

7y=42

y=42/7

y=6