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8y*5y=3000
We move all terms to the left:
8y*5y-(3000)=0
Wy multiply elements
40y^2-3000=0
a = 40; b = 0; c = -3000;
Δ = b2-4ac
Δ = 02-4·40·(-3000)
Δ = 480000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480000}=\sqrt{160000*3}=\sqrt{160000}*\sqrt{3}=400\sqrt{3}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-400\sqrt{3}}{2*40}=\frac{0-400\sqrt{3}}{80} =-\frac{400\sqrt{3}}{80} =-5\sqrt{3} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+400\sqrt{3}}{2*40}=\frac{0+400\sqrt{3}}{80} =\frac{400\sqrt{3}}{80} =5\sqrt{3} $
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