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3x+4(x+1)=5(x-1)+3
We move all terms to the left:
3x+4(x+1)-(5(x-1)+3)=0
We multiply parentheses
3x+4x-(5(x-1)+3)+4=0
We calculate terms in parentheses: -(5(x-1)+3), so:We add all the numbers together, and all the variables
5(x-1)+3
We multiply parentheses
5x-5+3
We add all the numbers together, and all the variables
5x-2
Back to the equation:
-(5x-2)
7x-(5x-2)+4=0
We get rid of parentheses
7x-5x+2+4=0
We add all the numbers together, and all the variables
2x+6=0
We move all terms containing x to the left, all other terms to the right
2x=-6
x=-6/2
x=-3
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