8(2x-4)=19x-(11x-8)

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Solution for 8(2x-4)=19x-(11x-8) equation: 



8(2x-4)=19x-(11x-8)

We move all terms to the left:

8(2x-4)-(19x-(11x-8))=0

We multiply parentheses

16x-(19x-(11x-8))-32=0



We calculate terms in parentheses: -(19x-(11x-8)), so:

19x-(11x-8)

We get rid of parentheses

19x-11x+8

We add all the numbers together, and all the variables

8x+8

Back to the equation:

-(8x+8)



We get rid of parentheses

16x-8x-8-32=0

We add all the numbers together, and all the variables

8x-40=0

We move all terms containing x to the left, all other terms to the right

8x=40

x=40/8

x=5

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