10+2(3x-2)=-10-2x

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Solution for 10+2(3x-2)=-10-2x equation: 



10+2(3x-2)=-10-2x

We move all terms to the left:

10+2(3x-2)-(-10-2x)=0

We add all the numbers together, and all the variables

2(3x-2)-(-2x-10)+10=0

We multiply parentheses

6x-(-2x-10)-4+10=0

We get rid of parentheses

6x+2x+10-4+10=0

We add all the numbers together, and all the variables

8x+16=0

We move all terms containing x to the left, all other terms to the right

8x=-16

x=-16/8

x=-2

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