8u2=+26u+2

Solution for 8u2=+26u+2 equation:

8u^2=+26u+2

We move all terms to the left:

8u^2-(+26u+2)=0

We add all the numbers together, and all the variables

8u^2-(26u+2)=0

We get rid of parentheses

8u^2-26u-2=0

a = 8; b = -26; c = -2;
Δ = b2-4ac
Δ = -262-4·8·(-2)
Δ = 740
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{740}=\sqrt{4*185}=\sqrt{4}*\sqrt{185}=2\sqrt{185}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{185}}{2*8}=\frac{26-2\sqrt{185}}{16}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{185}}{2*8}=\frac{26+2\sqrt{185}}{16}
$