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198=3x^2
We move all terms to the left:
198-(3x^2)=0
a = -3; b = 0; c = +198;
Δ = b2-4ac
Δ = 02-4·(-3)·198
Δ = 2376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2376}=\sqrt{36*66}=\sqrt{36}*\sqrt{66}=6\sqrt{66}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{66}}{2*-3}=\frac{0-6\sqrt{66}}{-6} =-\frac{6\sqrt{66}}{-6} =-\frac{\sqrt{66}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{66}}{2*-3}=\frac{0+6\sqrt{66}}{-6} =\frac{6\sqrt{66}}{-6} =\frac{\sqrt{66}}{-1} $
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