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15/08x-15/x=12
We move all terms to the left:
15/08x-15/x-(12)=0
Domain of the equation: 08x!=0
x!=0/08
x!=0
x∈R
Domain of the equation: x!=0We calculate fractions
x∈R
15x/8x^2+(-120x)/8x^2-12=0
We multiply all the terms by the denominator
15x+(-120x)-12*8x^2=0
Wy multiply elements
-96x^2+15x+(-120x)=0
We get rid of parentheses
-96x^2+15x-120x=0
We add all the numbers together, and all the variables
-96x^2-105x=0
a = -96; b = -105; c = 0;
Δ = b2-4ac
Δ = -1052-4·(-96)·0
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11025}=105$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-105}{2*-96}=\frac{0}{-192} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+105}{2*-96}=\frac{210}{-192} =-1+3/32 $
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