1+2(2-x)=3(x-5)

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Solution for 1+2(2-x)=3(x-5) equation: 



1+2(2-x)=3(x-5)

We move all terms to the left:

1+2(2-x)-(3(x-5))=0

We add all the numbers together, and all the variables

2(-1x+2)-(3(x-5))+1=0

We multiply parentheses

-2x-(3(x-5))+4+1=0



We calculate terms in parentheses: -(3(x-5)), so:

3(x-5)

We multiply parentheses

3x-15

Back to the equation:

-(3x-15)



We add all the numbers together, and all the variables

-2x-(3x-15)+5=0

We get rid of parentheses

-2x-3x+15+5=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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