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8c^2+34c+21=0
a = 8; b = 34; c = +21;
Δ = b2-4ac
Δ = 342-4·8·21
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-22}{2*8}=\frac{-56}{16} =-3+1/2 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+22}{2*8}=\frac{-12}{16} =-3/4 $
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