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(4s-7)(s+7)=0
We multiply parentheses ..
(+4s^2+28s-7s-49)=0
We get rid of parentheses
4s^2+28s-7s-49=0
We add all the numbers together, and all the variables
4s^2+21s-49=0
a = 4; b = 21; c = -49;
Δ = b2-4ac
Δ = 212-4·4·(-49)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-35}{2*4}=\frac{-56}{8} =-7 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+35}{2*4}=\frac{14}{8} =1+3/4 $
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