7=-11+(3b+15)

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Solution for 7=-11+(3b+15) equation:



7=-11+(3b+15)
We move all terms to the left:
7-(-11+(3b+15))=0
We calculate terms in parentheses: -(-11+(3b+15)), so:
-11+(3b+15)
determiningTheFunctionDomain (3b+15)-11
We get rid of parentheses
3b+15-11
We add all the numbers together, and all the variables
3b+4
Back to the equation:
-(3b+4)
We get rid of parentheses
-3b-4+7=0
We add all the numbers together, and all the variables
-3b+3=0
We move all terms containing b to the left, all other terms to the right
-3b=-3
b=-3/-3
b=1

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