(3m+2)(8m+7)=0

Solution for (3m+2)(8m+7)=0 equation:

(3m+2)(8m+7)=0

We multiply parentheses ..

(+24m^2+21m+16m+14)=0

We get rid of parentheses

24m^2+21m+16m+14=0

We add all the numbers together, and all the variables

24m^2+37m+14=0

a = 24; b = 37; c = +14;
Δ = b2-4ac
Δ = 372-4·24·14
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-5}{2*24}=\frac{-42}{48}
=-7/8
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+5}{2*24}=\frac{-32}{48}
=-2/3
$