6c(5c-2)=0

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Solution for 6c(5c-2)=0 equation:



6c(5c-2)=0
We multiply parentheses
30c^2-12c=0
a = 30; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·30·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*30}=\frac{0}{60} =0 $
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*30}=\frac{24}{60} =2/5 $

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