8-2(3-x)=16-(x+2)

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Solution for 8-2(3-x)=16-(x+2) equation: 



8-2(3-x)=16-(x+2)

We move all terms to the left:

8-2(3-x)-(16-(x+2))=0

We add all the numbers together, and all the variables

-2(-1x+3)-(16-(x+2))+8=0

We multiply parentheses

2x-(16-(x+2))-6+8=0



We calculate terms in parentheses: -(16-(x+2)), so:

16-(x+2)

determiningTheFunctionDomain
-(x+2)+16

We get rid of parentheses

-x-2+16

We add all the numbers together, and all the variables

-1x+14

Back to the equation:

-(-1x+14)



We add all the numbers together, and all the variables

2x-(-1x+14)+2=0

We get rid of parentheses

2x+1x-14+2=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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