110-10z=(z-5)

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Solution for 110-10z=(z-5) equation: 



110-10z=(z-5)

We move all terms to the left:

110-10z-((z-5))=0



We calculate terms in parentheses: -((z-5)), so:

(z-5)

We get rid of parentheses

z-5

Back to the equation:

-(z-5)



We get rid of parentheses

-10z-z+5+110=0

We add all the numbers together, and all the variables

-11z+115=0

We move all terms containing z to the left, all other terms to the right

-11z=-115

z=-115/-11

z=10+5/11

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