-2x-4(4-3x)=3(x-3)-35

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Solution for -2x-4(4-3x)=3(x-3)-35 equation: 



-2x-4(4-3x)=3(x-3)-35

We move all terms to the left:

-2x-4(4-3x)-(3(x-3)-35)=0

We add all the numbers together, and all the variables

-2x-4(-3x+4)-(3(x-3)-35)=0

We multiply parentheses

-2x+12x-(3(x-3)-35)-16=0



We calculate terms in parentheses: -(3(x-3)-35), so:

3(x-3)-35

We multiply parentheses

3x-9-35

We add all the numbers together, and all the variables

3x-44

Back to the equation:

-(3x-44)



We add all the numbers together, and all the variables

10x-(3x-44)-16=0

We get rid of parentheses

10x-3x+44-16=0

We add all the numbers together, and all the variables

7x+28=0

We move all terms containing x to the left, all other terms to the right

7x=-28

x=-28/7

x=-4

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