3/8(z-4)=-1/5(z+3)

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Solution for 3/8(z-4)=-1/5(z+3) equation: 



3/8(z-4)=-1/5(z+3)

We move all terms to the left:

3/8(z-4)-(-1/5(z+3))=0



Domain of the equation: 8(z-4)!=0

z∈R





Domain of the equation: 5(z+3))!=0

z∈R



We calculate fractions


(15zz/(8(z-4)*5(z+3)))+(-(-8zz)/(8(z-4)*5(z+3)))=0



We calculate terms in parentheses: +(15zz/(8(z-4)*5(z+3))), so:

15zz/(8(z-4)*5(z+3))

We multiply all the terms by the denominator


15zz

Back to the equation:

+(15zz)





We calculate terms in parentheses: +(-(-8zz)/(8(z-4)*5(z+3))), so:

-(-8zz)/(8(z-4)*5(z+3))

We multiply all the terms by the denominator


-(-8zz)

We get rid of parentheses

8zz

Back to the equation:

+(8zz)

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